13113201111300 has 216 divisors, whose sum is σ = 41239555812000. Its totient is φ = 3485217922560.

The previous prime is 13113201111289. The next prime is 13113201111341. The reversal of 13113201111300 is 311110231131.

13113201111300 is a `hidden beast` number, since 1 + 31 + 1 + 320 + 1 + 1 + 11 + 300 = 666.

13113201111300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 413662851 + ... + 413694549.

It is an arithmetic number, because the mean of its divisors is an integer number (190923869500).

Almost surely, 2^{13113201111300} is an apocalyptic number.

13113201111300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13113201111300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20619777906000).

13113201111300 is an abundant number, since it is smaller than the sum of its proper divisors (28126354700700).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13113201111300 is a wasteful number, since it uses less digits than its factorization.

13113201111300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33235 (or 33225 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 18.

Adding to 13113201111300 its reverse (311110231131), we get a palindrome (13424311342431).

The spelling of 13113201111300 in words is "thirteen trillion, one hundred thirteen billion, two hundred one million, one hundred eleven thousand, three hundred".