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13113201111289 is a prime number
BaseRepresentation
bin1011111011010010011110…
…1100011011000011111001
31201102121110112100210210221
42332310213230123003321
53204321313441030124
643520042121140041
72522253230230666
oct276644754330371
951377415323727
1013113201111289
1141a6306192124
12157951462a621
137417534228c6
1433497a402a6d
1517b1877ebce4
hexbed27b1b0f9

13113201111289 has 2 divisors, whose sum is σ = 13113201111290. Its totient is φ = 13113201111288.

The previous prime is 13113201111253. The next prime is 13113201111341. The reversal of 13113201111289 is 98211110231131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8026642595689 + 5086558515600 = 2833133^2 + 2255340^2 .

It is a cyclic number.

It is not a de Polignac number, because 13113201111289 - 211 = 13113201109241 is a prime.

It is a super-2 number, since 2×131132011112892 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13113201111209) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556600555644 + 6556600555645.

It is an arithmetic number, because the mean of its divisors is an integer number (6556600555645).

Almost surely, 213113201111289 is an apocalyptic number.

It is an amenable number.

13113201111289 is a deficient number, since it is larger than the sum of its proper divisors (1).

13113201111289 is an equidigital number, since it uses as much as digits as its factorization.

13113201111289 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 34.

The spelling of 13113201111289 in words is "thirteen trillion, one hundred thirteen billion, two hundred one million, one hundred eleven thousand, two hundred eighty-nine".