Base | Representation |
---|---|
bin | 1011111011010010100000… |
… | …1110010111111010111011 |
3 | 1201102121111011002222100211 |
4 | 2332310220032113322323 |
5 | 3204321323230330243 |
6 | 43520043040011551 |
7 | 2522253365666422 |
oct | 276645016277273 |
9 | 51377434088324 |
10 | 13113210011323 |
11 | 41a6310210924 |
12 | 1579517600bb7 |
13 | 74175521a8b6 |
14 | 33497b67c2b9 |
15 | 17b1884a8d9d |
hex | bed28397ebb |
13113210011323 has 2 divisors, whose sum is σ = 13113210011324. Its totient is φ = 13113210011322.
The previous prime is 13113210011287. The next prime is 13113210011357. The reversal of 13113210011323 is 32311001231131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13113210011323 - 29 = 13113210010811 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13113210011294 and 13113210011303.
It is not a weakly prime, because it can be changed into another prime (13113210011623) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556605005661 + 6556605005662.
It is an arithmetic number, because the mean of its divisors is an integer number (6556605005662).
Almost surely, 213113210011323 is an apocalyptic number.
13113210011323 is a deficient number, since it is larger than the sum of its proper divisors (1).
13113210011323 is an equidigital number, since it uses as much as digits as its factorization.
13113210011323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 13113210011323 its reverse (32311001231131), we get a palindrome (45424211242454).
The spelling of 13113210011323 in words is "thirteen trillion, one hundred thirteen billion, two hundred ten million, eleven thousand, three hundred twenty-three".
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