131132113201147 has 2 divisors, whose sum is σ = 131132113201148. Its totient is φ = 131132113201146.

The previous prime is 131132113201043. The next prime is 131132113201249. The reversal of 131132113201147 is 741102311231131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131132113201147 - 2¹¹ = 131132113199099 is a prime.

It is a super-2 number, since 2×131132113201147² (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131132113202147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65566056600573 + 65566056600574.

It is an arithmetic number, because the mean of its divisors is an integer number (65566056600574).

Almost surely, 2^{131132113201147} is an apocalyptic number.

131132113201147 is a deficient number, since it is larger than the sum of its proper divisors (1).

131132113201147 is an equidigital number, since it uses as much as digits as its factorization.

131132113201147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3024, while the sum is 31.

Adding to 131132113201147 its reverse (741102311231131), we get a palindrome (872234424432278).

The spelling of 131132113201147 in words is "one hundred thirty-one trillion, one hundred thirty-two billion, one hundred thirteen million, two hundred one thousand, one hundred forty-seven".