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131132200000 = 26552329983
BaseRepresentation
bin111101000100000010…
…1101001010001000000
3110112110211100222001011
41322020011221101000
54122024320400000
6140124042050304
712321402210664
oct1721005512100
9415424328034
10131132200000
115068178780a
12214b7aa9994
13c49a61a969
1464bd9ca8a4
15362745a2ba
hex1e88169440

131132200000 has 336 divisors, whose sum is σ = 351450005760. Its totient is φ = 48392960000.

The previous prime is 131132199959. The next prime is 131132200037. The reversal of 131132200000 is 2231131.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 133399509 + ... + 133400491.

It is an arithmetic number, because the mean of its divisors is an integer number (1045982160).

Almost surely, 2131132200000 is an apocalyptic number.

131132200000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131132200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (175725002880).

131132200000 is an abundant number, since it is smaller than the sum of its proper divisors (220317805760).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131132200000 is an frugal number, since it uses more digits than its factorization.

131132200000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1072 (or 1042 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 131132200000 its reverse (2231131), we get a palindrome (131134431131).

The spelling of 131132200000 in words is "one hundred thirty-one billion, one hundred thirty-two million, two hundred thousand".