Base | Representation |
---|---|
bin | 11101110100001110011110… |
… | …010011100011111011011001 |
3 | 122012022010101121211010210202 |
4 | 131310032132103203323121 |
5 | 114141432423411122301 |
6 | 1142521203104551545 |
7 | 36422665461520364 |
oct | 3564163623437331 |
9 | 565263347733722 |
10 | 131132302442201 |
11 | 38867996131145 |
12 | 1285a39a9225b5 |
13 | 5822952744188 |
14 | 2454ba17b70db |
15 | 10260bad7866b |
hex | 77439e4e3ed9 |
131132302442201 has 32 divisors (see below), whose sum is σ = 133588531964160. Its totient is φ = 128705128740864.
The previous prime is 131132302442189. The next prime is 131132302442287. The reversal of 131132302442201 is 102244203231131.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 131132302442201 - 222 = 131132298247897 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131132302442291) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 10693323596 + ... + 10693335858.
It is an arithmetic number, because the mean of its divisors is an integer number (4174641623880).
Almost surely, 2131132302442201 is an apocalyptic number.
It is an amenable number.
131132302442201 is a deficient number, since it is larger than the sum of its proper divisors (2456229521959).
131132302442201 is a wasteful number, since it uses less digits than its factorization.
131132302442201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14705.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 131132302442201 its reverse (102244203231131), we get a palindrome (233376505673332).
The spelling of 131132302442201 in words is "one hundred thirty-one trillion, one hundred thirty-two billion, three hundred two million, four hundred forty-two thousand, two hundred one".
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