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131132331200 = 26521331474327
BaseRepresentation
bin111101000100000011…
…0001001010011000000
3110112110211121122000102
41322020012021103000
54122024334044300
6140124044541532
712321403265333
oct1721006112300
9415424548012
10131132331200
1150681867342
12214b7b518a8
13c49a6655b0
1464bda2261a
1536274840d5
hex1e881894c0

131132331200 has 336 divisors, whose sum is σ = 366413881344. Its totient is φ = 45848678400.

The previous prime is 131132331199. The next prime is 131132331203. The reversal of 131132331200 is 2133231131.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is not an unprimeable number, because it can be changed into a prime (131132331203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 30303437 + ... + 30307763.

It is an arithmetic number, because the mean of its divisors is an integer number (1090517504).

Almost surely, 2131132331200 is an apocalyptic number.

131132331200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131132331200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (183206940672).

131132331200 is an abundant number, since it is smaller than the sum of its proper divisors (235281550144).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131132331200 is a wasteful number, since it uses less digits than its factorization.

131132331200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4440 (or 4425 counting only the distinct ones).

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 131132331200 its reverse (2133231131), we get a palindrome (133265562331).

It can be divided in two parts, 13113 and 2331200, that multiplied together give a square (30569025600 = 1748402).

The spelling of 131132331200 in words is "one hundred thirty-one billion, one hundred thirty-two million, three hundred thirty-one thousand, two hundred".