Search a number
-
+
1311324113 = 11119211283
BaseRepresentation
bin100111000101001…
…0011011111010001
310101101111011111202
41032022103133101
510141144332423
6334042120545
744332033241
oct11612233721
93341434452
101311324113
11613232240
123071b0155
1317b8a1438
14c622bb21
157a1ca728
hex4e2937d1

1311324113 has 4 divisors (see below), whose sum is σ = 1430535408. Its totient is φ = 1192112820.

The previous prime is 1311324109. The next prime is 1311324143. The reversal of 1311324113 is 3114231131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1311324113 - 22 = 1311324109 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1311324103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59605631 + ... + 59605652.

It is an arithmetic number, because the mean of its divisors is an integer number (357633852).

Almost surely, 21311324113 is an apocalyptic number.

It is an amenable number.

1311324113 is a deficient number, since it is larger than the sum of its proper divisors (119211295).

1311324113 is a wasteful number, since it uses less digits than its factorization.

1311324113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 119211294.

The product of its digits is 216, while the sum is 20.

The square root of 1311324113 is about 36212.2094465389. The cubic root of 1311324113 is about 1094.5527146024.

Adding to 1311324113 its reverse (3114231131), we get a palindrome (4425555244).

The spelling of 1311324113 in words is "one billion, three hundred eleven million, three hundred twenty-four thousand, one hundred thirteen".

Divisors: 1 11 119211283 1311324113