1311324109 has 2 divisors, whose sum is σ = 1311324110. Its totient is φ = 1311324108.

The previous prime is 1311324103. The next prime is 1311324143. The reversal of 1311324109 is 9014231131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1184874084 + 126450025 = 34422^2 + 11245^2 .

It is an emirp because it is prime and its reverse (9014231131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1311324109 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311324103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655662054 + 655662055.

It is an arithmetic number, because the mean of its divisors is an integer number (655662055).

Almost surely, 2^1311324109 is an apocalyptic number.

It is an amenable number.

1311324109 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311324109 is an equidigital number, since it uses as much as digits as its factorization.

1311324109 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 25.

The square root of 1311324109 is about 36212.2093913089. The cubic root of 1311324109 is about 1094.5527134895.

The spelling of 1311324109 in words is "one billion, three hundred eleven million, three hundred twenty-four thousand, one hundred nine".