1311324103 has 2 divisors, whose sum is σ = 1311324104. Its totient is φ = 1311324102.

The previous prime is 1311324097. The next prime is 1311324109. The reversal of 1311324103 is 3014231131.

It is a balanced prime because it is at equal distance from previous prime (1311324097) and next prime (1311324109).

It is an emirp because it is prime and its reverse (3014231131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1311324103 - 2¹³ = 1311315911 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311324109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655662051 + 655662052.

It is an arithmetic number, because the mean of its divisors is an integer number (655662052).

Almost surely, 2^1311324103 is an apocalyptic number.

1311324103 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311324103 is an equidigital number, since it uses as much as digits as its factorization.

1311324103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 19.

The square root of 1311324103 is about 36212.2093084639. The cubic root of 1311324103 is about 1094.5527118201.

Adding to 1311324103 its reverse (3014231131), we get a palindrome (4325555234).

The spelling of 1311324103 in words is "one billion, three hundred eleven million, three hundred twenty-four thousand, one hundred three".