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131132441081 is a prime number
BaseRepresentation
bin111101000100000011…
…0100100000111111001
3110112110211211012202002
41322020012210013321
54122024401103311
6140124051150345
712321404233565
oct1721006440771
9415424735662
10131132441081
1150681931954
12214b7ba53b5
13c49a6a3605
1464bda506a5
1536274a693b
hex1e881a41f9

131132441081 has 2 divisors, whose sum is σ = 131132441082. Its totient is φ = 131132441080.

The previous prime is 131132441023. The next prime is 131132441129. The reversal of 131132441081 is 180144231131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 104032696681 + 27099744400 = 322541^2 + 164620^2 .

It is a cyclic number.

It is not a de Polignac number, because 131132441081 - 218 = 131132178937 is a prime.

It is a super-2 number, since 2×1311324410812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131132441021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65566220540 + 65566220541.

It is an arithmetic number, because the mean of its divisors is an integer number (65566220541).

Almost surely, 2131132441081 is an apocalyptic number.

It is an amenable number.

131132441081 is a deficient number, since it is larger than the sum of its proper divisors (1).

131132441081 is an equidigital number, since it uses as much as digits as its factorization.

131132441081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 29.

The spelling of 131132441081 in words is "one hundred thirty-one billion, one hundred thirty-two million, four hundred forty-one thousand, eighty-one".