Base | Representation |
---|---|
bin | 10011000101010001100… |
… | …010110011000110111011 |
3 | 11122100210001120200112002 |
4 | 103011101202303012323 |
5 | 132441102233231021 |
6 | 2442230151211215 |
7 | 163512025312202 |
oct | 23052142630673 |
9 | 4570701520462 |
10 | 1311333102011 |
11 | 4661513934a9 |
12 | 19218a976b0b |
13 | 9687303c76a |
14 | 4767c7a8239 |
15 | 2419dd6150b |
hex | 131518b31bb |
1311333102011 has 2 divisors, whose sum is σ = 1311333102012. Its totient is φ = 1311333102010.
The previous prime is 1311333101999. The next prime is 1311333102019. The reversal of 1311333102011 is 1102013331131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1311333102011 is a prime.
It is not a weakly prime, because it can be changed into another prime (1311333102019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655666551005 + 655666551006.
It is an arithmetic number, because the mean of its divisors is an integer number (655666551006).
Almost surely, 21311333102011 is an apocalyptic number.
1311333102011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311333102011 is an equidigital number, since it uses as much as digits as its factorization.
1311333102011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 1311333102011 its reverse (1102013331131), we get a palindrome (2413346433142).
The spelling of 1311333102011 in words is "one trillion, three hundred eleven billion, three hundred thirty-three million, one hundred two thousand, eleven".
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