Base | Representation |
---|---|
bin | 11000011011001110… |
… | …11001010110001011 |
3 | 1020211220001100021212 |
4 | 30031213121112023 |
5 | 203324003130011 |
6 | 10005120123335 |
7 | 642650330633 |
oct | 141547312613 |
9 | 36756040255 |
10 | 13113333131 |
11 | 561a1532a8 |
12 | 265b76654b |
13 | 130ca03222 |
14 | 8c582b6c3 |
15 | 51b38c08b |
hex | 30d9d958b |
13113333131 has 2 divisors, whose sum is σ = 13113333132. Its totient is φ = 13113333130.
The previous prime is 13113333073. The next prime is 13113333139. The reversal of 13113333131 is 13133331131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13113333131 - 222 = 13109138827 is a prime.
It is a super-2 number, since 2×131133331312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13113333097 and 13113333106.
It is not a weakly prime, because it can be changed into another prime (13113333139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556666565 + 6556666566.
It is an arithmetic number, because the mean of its divisors is an integer number (6556666566).
Almost surely, 213113333131 is an apocalyptic number.
13113333131 is a deficient number, since it is larger than the sum of its proper divisors (1).
13113333131 is an equidigital number, since it uses as much as digits as its factorization.
13113333131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 729, while the sum is 23.
Adding to 13113333131 its reverse (13133331131), we get a palindrome (26246664262).
The spelling of 13113333131 in words is "thirteen billion, one hundred thirteen million, three hundred thirty-three thousand, one hundred thirty-one".
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