Base | Representation |
---|---|
bin | 111101000100000101… |
… | …0101010000101000110 |
3 | 110112110220211201120211 |
4 | 1322020022222011012 |
5 | 4122030134422204 |
6 | 140124130150034 |
7 | 12321416323024 |
oct | 1721012520506 |
9 | 415426751524 |
10 | 131133514054 |
11 | 506824a5004 |
12 | 214b842231a |
13 | c49a98aaca |
14 | 64bdc4d714 |
15 | 3627619804 |
hex | 1e882aa146 |
131133514054 has 4 divisors (see below), whose sum is σ = 196700271084. Its totient is φ = 65566757026.
The previous prime is 131133514037. The next prime is 131133514087. The reversal of 131133514054 is 450415331131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 450415331131 = 151579 ⋅2971489.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32783378512 + ... + 32783378515.
It is an arithmetic number, because the mean of its divisors is an integer number (49175067771).
Almost surely, 2131133514054 is an apocalyptic number.
131133514054 is a deficient number, since it is larger than the sum of its proper divisors (65566757030).
131133514054 is an equidigital number, since it uses as much as digits as its factorization.
131133514054 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65566757029.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 131133514054 its reverse (450415331131), we get a palindrome (581548845185).
The spelling of 131133514054 in words is "one hundred thirty-one billion, one hundred thirty-three million, five hundred fourteen thousand, fifty-four".
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