Base | Representation |
---|---|
bin | 11000011011001111… |
… | …00000001010000111 |
3 | 1020211220002202120012 |
4 | 30031213200022013 |
5 | 203324010023111 |
6 | 10005120500435 |
7 | 642650505161 |
oct | 141547401207 |
9 | 36756082505 |
10 | 13113361031 |
11 | 561a172261 |
12 | 265b77a71b |
13 | 130ca12b34 |
14 | 8c5837931 |
15 | 51b39548b |
hex | 30d9e0287 |
13113361031 has 4 divisors (see below), whose sum is σ = 13467776232. Its totient is φ = 12758945832.
The previous prime is 13113360979. The next prime is 13113361039. The reversal of 13113361031 is 13016331131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13113361031 is a prime.
It is a super-2 number, since 2×131133610312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13113360988 and 13113361006.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13113361039) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 177207545 + ... + 177207618.
It is an arithmetic number, because the mean of its divisors is an integer number (3366944058).
Almost surely, 213113361031 is an apocalyptic number.
13113361031 is a deficient number, since it is larger than the sum of its proper divisors (354415201).
13113361031 is an equidigital number, since it uses as much as digits as its factorization.
13113361031 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 354415200.
The product of its (nonzero) digits is 486, while the sum is 23.
Adding to 13113361031 its reverse (13016331131), we get a palindrome (26129692162).
The spelling of 13113361031 in words is "thirteen billion, one hundred thirteen million, three hundred sixty-one thousand, thirty-one".
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