13113361030 has 64 divisors (see below), whose sum is σ = 29465607168. Its totient is φ = 4082117760.

The previous prime is 13113360979. The next prime is 13113361039. The reversal of 13113361030 is 3016331131.

It is a Harshad number since it is a multiple of its sum of digits (22).

It is a junction number, because it is equal to n+sod(n) for n = 13113360992 and 13113361010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13113361039) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 623364 + ... + 644056.

It is an arithmetic number, because the mean of its divisors is an integer number (460400112).

Almost surely, 2^13113361030 is an apocalyptic number.

13113361030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13113361030 is an abundant number, since it is smaller than the sum of its proper divisors (16352246138).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13113361030 is a wasteful number, since it uses less digits than its factorization.

13113361030 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21541.

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 13113361030 its reverse (3016331131), we get a palindrome (16129692161).

The spelling of 13113361030 in words is "thirteen billion, one hundred thirteen million, three hundred sixty-one thousand, thirty".