13113400550115 has 16 divisors (see below), whose sum is σ = 21893677440768. Its totient is φ = 6689734773216.

The previous prime is 13113400550083. The next prime is 13113400550119. The reversal of 13113400550115 is 51105500431131.

It is not a de Polignac number, because 13113400550115 - 2⁵ = 13113400550083 is a prime.

It is a super-2 number, since 2×13113400550115² (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13113400550119) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 19004927989 + ... + 19004928678.

It is an arithmetic number, because the mean of its divisors is an integer number (1368354840048).

Almost surely, 2^{13113400550115} is an apocalyptic number.

13113400550115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

13113400550115 is a deficient number, since it is larger than the sum of its proper divisors (8780276890653).

13113400550115 is a wasteful number, since it uses less digits than its factorization.

13113400550115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38009856698.

The product of its (nonzero) digits is 4500, while the sum is 30.

Adding to 13113400550115 its reverse (51105500431131), we get a palindrome (64218900981246).

The spelling of 13113400550115 in words is "thirteen trillion, one hundred thirteen billion, four hundred million, five hundred fifty thousand, one hundred fifteen".