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131134313503043 is a prime number
BaseRepresentation
bin11101110100010000010110…
…001011001001100101000011
3122012022022120202222121122122
4131310100112023021211003
5114142001033224044133
61142522134424554455
736423066351330464
oct3564202613114503
9565268522877578
10131134313503043
11388688283429a4
121285a860322a2b
135822bb3291bc6
142454d12910d6b
1510261876c3498
hex7744162c9943

131134313503043 has 2 divisors, whose sum is σ = 131134313503044. Its totient is φ = 131134313503042.

The previous prime is 131134313502887. The next prime is 131134313503099. The reversal of 131134313503043 is 340305313431131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131134313503043 - 210 = 131134313502019 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131134313502994 and 131134313503012.

It is not a weakly prime, because it can be changed into another prime (131134313505043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65567156751521 + 65567156751522.

It is an arithmetic number, because the mean of its divisors is an integer number (65567156751522).

Almost surely, 2131134313503043 is an apocalyptic number.

131134313503043 is a deficient number, since it is larger than the sum of its proper divisors (1).

131134313503043 is an equidigital number, since it uses as much as digits as its factorization.

131134313503043 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 58320, while the sum is 35.

Adding to 131134313503043 its reverse (340305313431131), we get a palindrome (471439626934174).

The spelling of 131134313503043 in words is "one hundred thirty-one trillion, one hundred thirty-four billion, three hundred thirteen million, five hundred three thousand, forty-three".