1311343503 has 4 divisors (see below), whose sum is σ = 1748458008. Its totient is φ = 874229000.

The previous prime is 1311343483. The next prime is 1311343519. The reversal of 1311343503 is 3053431131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1311343503 - 2⁵ = 1311343471 is a prime.

It is a super-2 number, since 2×1311343503² = 3439243565720622018, which contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311343403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218557248 + ... + 218557253.

It is an arithmetic number, because the mean of its divisors is an integer number (437114502).

Almost surely, 2^1311343503 is an apocalyptic number.

1311343503 is a deficient number, since it is larger than the sum of its proper divisors (437114505).

1311343503 is an equidigital number, since it uses as much as digits as its factorization.

1311343503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 437114504.

The product of its (nonzero) digits is 1620, while the sum is 24.

The square root of 1311343503 is about 36212.4771729303. The cubic root of 1311343503 is about 1094.5581094732.

Adding to 1311343503 its reverse (3053431131), we get a palindrome (4364774634).

It can be divided in two parts, 13113 and 43503, that added together give a triangular number (56616 = T₃₃₆).

The spelling of 1311343503 in words is "one billion, three hundred eleven million, three hundred forty-three thousand, five hundred three".