Base | Representation |
---|---|
bin | 1011111011010011010110… |
… | …1001110111000011010111 |
3 | 1201102122001212001212111110 |
4 | 2332310311221313003113 |
5 | 3204322303420224120 |
6 | 43520121245110103 |
7 | 2522262103044534 |
oct | 276646551670327 |
9 | 51378055055443 |
10 | 13113435320535 |
11 | 41a641640aa90 |
12 | 157957ab58333 |
13 | 74178cac6a64 |
14 | 33499d56bd8b |
15 | 17b19d1622e0 |
hex | bed35a770d7 |
13113435320535 has 32 divisors (see below), whose sum is σ = 22889211890688. Its totient is φ = 6357944078720.
The previous prime is 13113435320521. The next prime is 13113435320653. The reversal of 13113435320535 is 53502353431131.
It is not a de Polignac number, because 13113435320535 - 213 = 13113435312343 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13113435320493 and 13113435320502.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 12837289 + ... + 13821101.
It is an arithmetic number, because the mean of its divisors is an integer number (715287871584).
Almost surely, 213113435320535 is an apocalyptic number.
13113435320535 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13113435320535 is a deficient number, since it is larger than the sum of its proper divisors (9775776570153).
13113435320535 is a wasteful number, since it uses less digits than its factorization.
13113435320535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1064615.
The product of its (nonzero) digits is 243000, while the sum is 39.
Adding to 13113435320535 its reverse (53502353431131), we get a palindrome (66615788751666).
The spelling of 13113435320535 in words is "thirteen trillion, one hundred thirteen billion, four hundred thirty-five million, three hundred twenty thousand, five hundred thirty-five".
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