Base | Representation |
---|---|
bin | 111101000100001110… |
… | …0110101000110000101 |
3 | 110112111020210202011120 |
4 | 1322020130311012011 |
5 | 4122032344342030 |
6 | 140124420224153 |
7 | 12321504653265 |
oct | 1721034650605 |
9 | 415436722146 |
10 | 131138277765 |
11 | 50685159060 |
12 | 214b9b3b059 |
13 | c49b968181 |
14 | 64c072d7a5 |
15 | 3627c5b010 |
hex | 1e88735185 |
131138277765 has 32 divisors (see below), whose sum is σ = 229204187136. Its totient is φ = 63496560960.
The previous prime is 131138277757. The next prime is 131138277769. The reversal of 131138277765 is 567772831131.
It is not a de Polignac number, because 131138277765 - 23 = 131138277757 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131138277769) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 412249 + ... + 657438.
It is an arithmetic number, because the mean of its divisors is an integer number (7162630848).
Almost surely, 2131138277765 is an apocalyptic number.
131138277765 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
131138277765 is a deficient number, since it is larger than the sum of its proper divisors (98065909371).
131138277765 is a wasteful number, since it uses less digits than its factorization.
131138277765 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1070449.
The product of its digits is 1481760, while the sum is 51.
The spelling of 131138277765 in words is "one hundred thirty-one billion, one hundred thirty-eight million, two hundred seventy-seven thousand, seven hundred sixty-five".
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