13114022425022 has 4 divisors (see below), whose sum is σ = 19671033637536. Its totient is φ = 6557011212510.

The previous prime is 13114022425013. The next prime is 13114022425037. The reversal of 13114022425022 is 22052422041131.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×13114022425022³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3278505606254 + ... + 3278505606257.

It is an arithmetic number, because the mean of its divisors is an integer number (4917758409384).

Almost surely, 2^{13114022425022} is an apocalyptic number.

13114022425022 is a deficient number, since it is larger than the sum of its proper divisors (6557011212514).

13114022425022 is an equidigital number, since it uses as much as digits as its factorization.

13114022425022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6557011212513.

The product of its (nonzero) digits is 7680, while the sum is 29.

Adding to 13114022425022 its reverse (22052422041131), we get a palindrome (35166444466153).

The spelling of 13114022425022 in words is "thirteen trillion, one hundred fourteen billion, twenty-two million, four hundred twenty-five thousand, twenty-two".