Base | Representation |
---|---|
bin | 11101110100010101111011… |
… | …010100110110011001101011 |
3 | 122012022220001101000012201220 |
4 | 131310111323110312121223 |
5 | 114142100321202341133 |
6 | 1142525005154313123 |
7 | 36423401010504462 |
oct | 3564257324663153 |
9 | 565286041005656 |
10 | 131140305512043 |
11 | 38870322705a53 |
12 | 1285ba52b887a3 |
13 | 58236297c0669 |
14 | 245532063d9d9 |
15 | 10263d877d5b3 |
hex | 77457b53666b |
131140305512043 has 32 divisors (see below), whose sum is σ = 180121653331200. Its totient is φ = 84834609209856.
The previous prime is 131140305512023. The next prime is 131140305512119. The reversal of 131140305512043 is 340215503041131.
It is not a de Polignac number, because 131140305512043 - 214 = 131140305495659 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131140305511995 and 131140305512013.
It is not an unprimeable number, because it can be changed into a prime (131140305512023) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2156055 + ... + 16337967.
It is an arithmetic number, because the mean of its divisors is an integer number (5628801666600).
Almost surely, 2131140305512043 is an apocalyptic number.
131140305512043 is a deficient number, since it is larger than the sum of its proper divisors (48981347819157).
131140305512043 is a wasteful number, since it uses less digits than its factorization.
131140305512043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14182651.
The product of its (nonzero) digits is 21600, while the sum is 33.
Adding to 131140305512043 its reverse (340215503041131), we get a palindrome (471355808553174).
The spelling of 131140305512043 in words is "one hundred thirty-one trillion, one hundred forty billion, three hundred five million, five hundred twelve thousand, forty-three".
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