Base | Representation |
---|---|
bin | 11101110100010101111011… |
… | …010100110110011001101010 |
3 | 122012022220001101000012201212 |
4 | 131310111323110312121222 |
5 | 114142100321202341132 |
6 | 1142525005154313122 |
7 | 36423401010504461 |
oct | 3564257324663152 |
9 | 565286041005655 |
10 | 131140305512042 |
11 | 38870322705a52 |
12 | 1285ba52b887a2 |
13 | 58236297c0668 |
14 | 245532063d9d8 |
15 | 10263d877d5b2 |
hex | 77457b53666a |
131140305512042 has 4 divisors (see below), whose sum is σ = 196710458268066. Its totient is φ = 65570152756020.
The previous prime is 131140305512023. The next prime is 131140305512119. The reversal of 131140305512042 is 240215503041131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 102775211871721 + 28365093640321 = 10137811^2 + 5325889^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32785076378009 + ... + 32785076378012.
Almost surely, 2131140305512042 is an apocalyptic number.
131140305512042 is a deficient number, since it is larger than the sum of its proper divisors (65570152756024).
131140305512042 is an equidigital number, since it uses as much as digits as its factorization.
131140305512042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65570152756023.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 131140305512042 its reverse (240215503041131), we get a palindrome (371355808553173).
The spelling of 131140305512042 in words is "one hundred thirty-one trillion, one hundred forty billion, three hundred five million, five hundred twelve thousand, forty-two".
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