Base | Representation |
---|---|
bin | 11101110100010101111011… |
… | …110110011111101101111001 |
3 | 122012022220001222121022110220 |
4 | 131310111323312133231321 |
5 | 114142100330432111100 |
6 | 1142525010111330253 |
7 | 36423401145460635 |
oct | 3564257366375571 |
9 | 565286058538426 |
10 | 131140314332025 |
11 | 3887032768a599 |
12 | 1285ba55b20989 |
13 | 582362b58b09b |
14 | 2455321897dc5 |
15 | 10263d9421aa0 |
hex | 77457bd9fb79 |
131140314332025 has 12 divisors (see below), whose sum is σ = 216818653029072. Its totient is φ = 69941500977040.
The previous prime is 131140314332003. The next prime is 131140314332171. The reversal of 131140314332025 is 520233413041131.
It is not a de Polignac number, because 131140314332025 - 29 = 131140314331513 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 874268762139 + ... + 874268762288.
It is an arithmetic number, because the mean of its divisors is an integer number (18068221085756).
Almost surely, 2131140314332025 is an apocalyptic number.
131140314332025 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
131140314332025 is a deficient number, since it is larger than the sum of its proper divisors (85678338697047).
131140314332025 is a wasteful number, since it uses less digits than its factorization.
131140314332025 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1748537524440 (or 1748537524435 counting only the distinct ones).
The product of its (nonzero) digits is 25920, while the sum is 33.
Adding to 131140314332025 its reverse (520233413041131), we get a palindrome (651373727373156).
The spelling of 131140314332025 in words is "one hundred thirty-one trillion, one hundred forty billion, three hundred fourteen million, three hundred thirty-two thousand, twenty-five".
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