131140314331513 has 2 divisors, whose sum is σ = 131140314331514. Its totient is φ = 131140314331512.

The previous prime is 131140314331511. The next prime is 131140314331603. The reversal of 131140314331513 is 315133413041131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 130182897091984 + 957417239529 = 11409772^2 + 978477^2 .

It is a cyclic number.

It is not a de Polignac number, because 131140314331513 - 2¹ = 131140314331511 is a prime.

It is a super-3 number, since 3×131140314331513³ (a number of 43 digits) contains 333 as substring.

Together with 131140314331511, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (131140314331511) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570157165756 + 65570157165757.

It is an arithmetic number, because the mean of its divisors is an integer number (65570157165757).

Almost surely, 2^{131140314331513} is an apocalyptic number.

It is an amenable number.

131140314331513 is a deficient number, since it is larger than the sum of its proper divisors (1).

131140314331513 is an equidigital number, since it uses as much as digits as its factorization.

131140314331513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19440, while the sum is 34.

Adding to 131140314331513 its reverse (315133413041131), we get a palindrome (446273727372644).

The spelling of 131140314331513 in words is "one hundred thirty-one trillion, one hundred forty billion, three hundred fourteen million, three hundred thirty-one thousand, five hundred thirteen".