Base | Representation |
---|---|
bin | 100111000101010… |
… | …0110110010010001 |
3 | 10101101122011221011 |
4 | 1032022212302101 |
5 | 10141204400103 |
6 | 334043530521 |
7 | 44332512544 |
oct | 11612466221 |
9 | 3341564834 |
10 | 1311403153 |
11 | 613286665 |
12 | 307229a41 |
13 | 17b8cb3c8 |
14 | c624c85b |
15 | 7a1e3d6d |
hex | 4e2a6c91 |
1311403153 has 2 divisors, whose sum is σ = 1311403154. Its totient is φ = 1311403152.
The previous prime is 1311403147. The next prime is 1311403169. The reversal of 1311403153 is 3513041131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1152466704 + 158936449 = 33948^2 + 12607^2 .
It is an emirp because it is prime and its reverse (3513041131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1311403153 - 213 = 1311394961 is a prime.
It is not a weakly prime, because it can be changed into another prime (1311403253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655701576 + 655701577.
It is an arithmetic number, because the mean of its divisors is an integer number (655701577).
Almost surely, 21311403153 is an apocalyptic number.
It is an amenable number.
1311403153 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311403153 is an equidigital number, since it uses as much as digits as its factorization.
1311403153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 22.
The square root of 1311403153 is about 36213.3007747154. The cubic root of 1311403153 is about 1094.5747055319.
Adding to 1311403153 its reverse (3513041131), we get a palindrome (4824444284).
The spelling of 1311403153 in words is "one billion, three hundred eleven million, four hundred three thousand, one hundred fifty-three".
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