Base | Representation |
---|---|
bin | 1011111011010101110101… |
… | …0100101110101101111001 |
3 | 1201102200210020102021201222 |
4 | 2332311131110232231321 |
5 | 3204330134310320014 |
6 | 43520311302121425 |
7 | 2522314434113156 |
oct | 276653524565571 |
9 | 51380706367658 |
10 | 13114100870009 |
11 | 41a672806a177 |
12 | 1579725a20275 |
13 | 741867963509 |
14 | 334a23ad922d |
15 | 17b1db7cc08e |
hex | bed5d52eb79 |
13114100870009 has 2 divisors, whose sum is σ = 13114100870010. Its totient is φ = 13114100870008.
The previous prime is 13114100869967. The next prime is 13114100870053. The reversal of 13114100870009 is 90007800141131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12098849155600 + 1015251714409 = 3478340^2 + 1007597^2 .
It is a cyclic number.
It is not a de Polignac number, because 13114100870009 - 216 = 13114100804473 is a prime.
It is not a weakly prime, because it can be changed into another prime (13114100810009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557050435004 + 6557050435005.
It is an arithmetic number, because the mean of its divisors is an integer number (6557050435005).
Almost surely, 213114100870009 is an apocalyptic number.
It is an amenable number.
13114100870009 is a deficient number, since it is larger than the sum of its proper divisors (1).
13114100870009 is an equidigital number, since it uses as much as digits as its factorization.
13114100870009 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 35.
The spelling of 13114100870009 in words is "thirteen trillion, one hundred fourteen billion, one hundred million, eight hundred seventy thousand, nine".
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