Base | Representation |
---|---|
bin | 11101110100010110101011… |
… | …011001011100011111100011 |
3 | 122012022222010120121012210111 |
4 | 131310112223121130133203 |
5 | 114142103444134214021 |
6 | 1142525221204512151 |
7 | 36423430002646426 |
oct | 3564265331343743 |
9 | 565288116535714 |
10 | 131141112023011 |
11 | 388706a6993642 |
12 | 128600390ab657 |
13 | 5823727912c9c |
14 | 24553997c19bd |
15 | 102643448e8e1 |
hex | 7745ab65c7e3 |
131141112023011 has 2 divisors, whose sum is σ = 131141112023012. Its totient is φ = 131141112023010.
The previous prime is 131141112022981. The next prime is 131141112023057. The reversal of 131141112023011 is 110320211141131.
It is a weak prime.
It is an emirp because it is prime and its reverse (110320211141131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131141112023011 - 27 = 131141112022883 is a prime.
It is a super-2 number, since 2×1311411120230112 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131141112063011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570556011505 + 65570556011506.
It is an arithmetic number, because the mean of its divisors is an integer number (65570556011506).
Almost surely, 2131141112023011 is an apocalyptic number.
131141112023011 is a deficient number, since it is larger than the sum of its proper divisors (1).
131141112023011 is an equidigital number, since it uses as much as digits as its factorization.
131141112023011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 22.
Adding to 131141112023011 its reverse (110320211141131), we get a palindrome (241461323164142).
The spelling of 131141112023011 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred twelve million, twenty-three thousand, eleven".
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