Base | Representation |
---|---|
bin | 11101110100010110101011… |
… | …011001100000111000101001 |
3 | 122012022222010120122010110210 |
4 | 131310112223121200320221 |
5 | 114142103444140303001 |
6 | 1142525221205131333 |
7 | 36423430003053036 |
oct | 3564265331407051 |
9 | 565288116563423 |
10 | 131141112041001 |
11 | 388706a69a6107 |
12 | 128600390b9b49 |
13 | 582372791b22a |
14 | 24553997c838d |
15 | 1026434494dd6 |
hex | 7745ab660e29 |
131141112041001 has 8 divisors (see below), whose sum is σ = 174855034345600. Its totient is φ = 87427298881872.
The previous prime is 131141112040973. The next prime is 131141112041003. The reversal of 131141112041001 is 100140211141131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 131141112041001 - 25 = 131141112040969 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131141112041003) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24440401 + ... + 29319198.
It is an arithmetic number, because the mean of its divisors is an integer number (21856879293200).
Almost surely, 2131141112041001 is an apocalyptic number.
It is an amenable number.
131141112041001 is a deficient number, since it is larger than the sum of its proper divisors (43713922304599).
131141112041001 is an equidigital number, since it uses as much as digits as its factorization.
131141112041001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54572735.
The product of its (nonzero) digits is 96, while the sum is 21.
Adding to 131141112041001 its reverse (100140211141131), we get a palindrome (231281323182132).
The spelling of 131141112041001 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred twelve million, forty-one thousand, one".
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