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131141112040973 is a prime number
BaseRepresentation
bin11101110100010110101011…
…011001100000111000001101
3122012022222010120122010102202
4131310112223121200320031
5114142103444140302343
61142525221205131245
736423430003052666
oct3564265331407015
9565288116563382
10131141112040973
11388706a69a6091
12128600390b9b25
13582372791b208
1424553997c836d
151026434494db8
hex7745ab660e0d

131141112040973 has 2 divisors, whose sum is σ = 131141112040974. Its totient is φ = 131141112040972.

The previous prime is 131141112040969. The next prime is 131141112041003. The reversal of 131141112040973 is 379040211141131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 113400732444484 + 17740379596489 = 10648978^2 + 4211933^2 .

It is a cyclic number.

It is not a de Polignac number, because 131141112040973 - 22 = 131141112040969 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131141112040903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570556020486 + 65570556020487.

It is an arithmetic number, because the mean of its divisors is an integer number (65570556020487).

Almost surely, 2131141112040973 is an apocalyptic number.

It is an amenable number.

131141112040973 is a deficient number, since it is larger than the sum of its proper divisors (1).

131141112040973 is an equidigital number, since it uses as much as digits as its factorization.

131141112040973 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18144, while the sum is 38.

The spelling of 131141112040973 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred twelve million, forty thousand, nine hundred seventy-three".