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131141112234241 is a prime number
BaseRepresentation
bin11101110100010110101011…
…011010010000000100000001
3122012022222010120222221112211
4131310112223122100010001
5114142103444212443431
61142525221213222121
736423430004516314
oct3564265332200401
9565288116887484
10131141112234241
11388706a701830a
1212860039191941
135823727988185
14245539983897b
1510264344d22b1
hex7745ab690101

131141112234241 has 2 divisors, whose sum is σ = 131141112234242. Its totient is φ = 131141112234240.

The previous prime is 131141112234227. The next prime is 131141112234263. The reversal of 131141112234241 is 142432211141131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 73352304643216 + 57788807591025 = 8564596^2 + 7601895^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131141112234241 is a prime.

It is not a weakly prime, because it can be changed into another prime (131141112234211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570556117120 + 65570556117121.

It is an arithmetic number, because the mean of its divisors is an integer number (65570556117121).

Almost surely, 2131141112234241 is an apocalyptic number.

It is an amenable number.

131141112234241 is a deficient number, since it is larger than the sum of its proper divisors (1).

131141112234241 is an equidigital number, since it uses as much as digits as its factorization.

131141112234241 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4608, while the sum is 31.

Adding to 131141112234241 its reverse (142432211141131), we get a palindrome (273573323375372).

The spelling of 131141112234241 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred twelve million, two hundred thirty-four thousand, two hundred forty-one".