13114111233441 has 4 divisors (see below), whose sum is σ = 17485481644592. Its totient is φ = 8742740822292.

The previous prime is 13114111233439. The next prime is 13114111233449. The reversal of 13114111233441 is 14433211141131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13114111233441 - 2¹ = 13114111233439 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13114111233399 and 13114111233408.

It is not an unprimeable number, because it can be changed into a prime (13114111233449) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2185685205571 + ... + 2185685205576.

It is an arithmetic number, because the mean of its divisors is an integer number (4371370411148).

Almost surely, 2^{13114111233441} is an apocalyptic number.

It is an amenable number.

13114111233441 is a deficient number, since it is larger than the sum of its proper divisors (4371370411151).

13114111233441 is an equidigital number, since it uses as much as digits as its factorization.

13114111233441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4371370411150.

The product of its digits is 3456, while the sum is 30.

Adding to 13114111233441 its reverse (14433211141131), we get a palindrome (27547322374572).

The spelling of 13114111233441 in words is "thirteen trillion, one hundred fourteen billion, one hundred eleven million, two hundred thirty-three thousand, four hundred forty-one".