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13114111443442 = 2431153132254699
BaseRepresentation
bin1011111011010101110111…
…1101000100000111110010
31201102200210222022110202121
42332311131331010013302
53204330200012142232
643520312320504454
72522314623021412
oct276653575040762
951380728273677
1013114111443442
1141a6733031149
12157972947b12a
13741869bc6099
14334a2528c642
1517b1dc6b9d97
hexbed5df441f2

13114111443442 has 16 divisors (see below), whose sum is σ = 20146093941600. Its totient is φ = 6399011308032.

The previous prime is 13114111443431. The next prime is 13114111443443. The reversal of 13114111443442 is 24434411141131.

It is a super-3 number, since 3×131141114434423 (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13114111443398 and 13114111443407.

It is not an unprimeable number, because it can be changed into a prime (13114111443443) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 66028192 + ... + 66226507.

It is an arithmetic number, because the mean of its divisors is an integer number (1259130871350).

Almost surely, 213114111443442 is an apocalyptic number.

13114111443442 is a deficient number, since it is larger than the sum of its proper divisors (7031982498158).

13114111443442 is a wasteful number, since it uses less digits than its factorization.

13114111443442 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 132255897.

The product of its digits is 18432, while the sum is 34.

Adding to 13114111443442 its reverse (24434411141131), we get a palindrome (37548522584573).

The spelling of 13114111443442 in words is "thirteen trillion, one hundred fourteen billion, one hundred eleven million, four hundred forty-three thousand, four hundred forty-two".

Divisors: 1 2 43 86 1153 2306 49579 99158 132254699 264509398 5686952057 11373904114 152489667947 304979335894 6557055721721 13114111443442