Base | Representation |
---|---|
bin | 1011111011010101111000… |
… | …0110111001011100011011 |
3 | 1201102200211011011102201011 |
4 | 2332311132012321130123 |
5 | 3204330201142134042 |
6 | 43520312452034351 |
7 | 2522314653645526 |
oct | 276653606713433 |
9 | 51380734142634 |
10 | 13114114021147 |
11 | 41a6734531887 |
12 | 157972a3029b7 |
13 | 74186a5b9459 |
14 | 334a2575dbbd |
15 | 17b1dca28a17 |
hex | bed5e1b971b |
13114114021147 has 2 divisors, whose sum is σ = 13114114021148. Its totient is φ = 13114114021146.
The previous prime is 13114114021117. The next prime is 13114114021159. The reversal of 13114114021147 is 74112041141131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13114114021147 - 219 = 13114113496859 is a prime.
It is not a weakly prime, because it can be changed into another prime (13114114021117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557057010573 + 6557057010574.
It is an arithmetic number, because the mean of its divisors is an integer number (6557057010574).
Almost surely, 213114114021147 is an apocalyptic number.
13114114021147 is a deficient number, since it is larger than the sum of its proper divisors (1).
13114114021147 is an equidigital number, since it uses as much as digits as its factorization.
13114114021147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2688, while the sum is 31.
Adding to 13114114021147 its reverse (74112041141131), we get a palindrome (87226155162278).
The spelling of 13114114021147 in words is "thirteen trillion, one hundred fourteen billion, one hundred fourteen million, twenty-one thousand, one hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •