13114130034340 has 12 divisors (see below), whose sum is σ = 27539673072156. Its totient is φ = 5245652013728.

The previous prime is 13114130034337. The next prime is 13114130034347. The reversal of 13114130034340 is 4343003141131.

It can be written as a sum of positive squares in 2 ways, for example, as 5819171991616 + 7294958042724 = 2412296^2 + 2700918^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13114130034299 and 13114130034308.

It is not an unprimeable number, because it can be changed into a prime (13114130034347) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 327853250839 + ... + 327853250878.

It is an arithmetic number, because the mean of its divisors is an integer number (2294972756013).

Almost surely, 2^{13114130034340} is an apocalyptic number.

13114130034340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13114130034340 is an abundant number, since it is smaller than the sum of its proper divisors (14425543037816).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13114130034340 is a wasteful number, since it uses less digits than its factorization.

13114130034340 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 655706501726 (or 655706501724 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 13114130034340 its reverse (4343003141131), we get a palindrome (17457133175471).

The spelling of 13114130034340 in words is "thirteen trillion, one hundred fourteen billion, one hundred thirty million, thirty-four thousand, three hundred forty".