131141324011081 has 2 divisors, whose sum is σ = 131141324011082. Its totient is φ = 131141324011080.

The previous prime is 131141324011067. The next prime is 131141324011121. The reversal of 131141324011081 is 180110423141131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 127832985005625 + 3308339005456 = 11306325^2 + 1818884^2 .

It is a cyclic number.

It is not a de Polignac number, because 131141324011081 - 2⁷ = 131141324010953 is a prime.

It is a super-3 number, since 3×131141324011081³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (131141324011021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570662005540 + 65570662005541.

It is an arithmetic number, because the mean of its divisors is an integer number (65570662005541).

Almost surely, 2^{131141324011081} is an apocalyptic number.

It is an amenable number.

131141324011081 is a deficient number, since it is larger than the sum of its proper divisors (1).

131141324011081 is an equidigital number, since it uses as much as digits as its factorization.

131141324011081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 31.

The spelling of 131141324011081 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred twenty-four million, eleven thousand, eighty-one".