Base | Representation |
---|---|
bin | 1011111011010101111100… |
… | …1101001000001000110001 |
3 | 1201102200212102210202211201 |
4 | 2332311133031020020301 |
5 | 3204330220400301114 |
6 | 43520314350411201 |
7 | 2522315266304002 |
oct | 276653715101061 |
9 | 51380772722751 |
10 | 13114132431409 |
11 | 41a6743966779 |
12 | 1579734500b01 |
13 | 7418713640b9 |
14 | 334a27d931a9 |
15 | 17b1de463874 |
hex | bed5f348231 |
13114132431409 has 2 divisors, whose sum is σ = 13114132431410. Its totient is φ = 13114132431408.
The previous prime is 13114132431403. The next prime is 13114132431443. The reversal of 13114132431409 is 90413423141131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12740723442225 + 373408989184 = 3569415^2 + 611072^2 .
It is an emirp because it is prime and its reverse (90413423141131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13114132431409 - 25 = 13114132431377 is a prime.
It is not a weakly prime, because it can be changed into another prime (13114132431403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557066215704 + 6557066215705.
It is an arithmetic number, because the mean of its divisors is an integer number (6557066215705).
Almost surely, 213114132431409 is an apocalyptic number.
It is an amenable number.
13114132431409 is a deficient number, since it is larger than the sum of its proper divisors (1).
13114132431409 is an equidigital number, since it uses as much as digits as its factorization.
13114132431409 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31104, while the sum is 37.
The spelling of 13114132431409 in words is "thirteen trillion, one hundred fourteen billion, one hundred thirty-two million, four hundred thirty-one thousand, four hundred nine".
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