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131141324341442 = 267978666599563
BaseRepresentation
bin11101110100010110111000…
…000011011000000011000010
3122012022222200101010002221002
4131310112320003120003002
5114142104413012411232
61142525254231332002
736423435161430542
oct3564267003300302
9565288611102832
10131141324341442
11388707a581a618
1212860098221002
13582375c8c11ac
1424553b9a8d322
151026447e2db62
hex7745b80d80c2

131141324341442 has 8 divisors (see below), whose sum is σ = 199647986311056. Its totient is φ = 64591995571092.

The previous prime is 131141324341411. The next prime is 131141324341451. The reversal of 131141324341442 is 244143423141131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 131141324341396 and 131141324341405.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 489333299648 + ... + 489333299915.

It is an arithmetic number, because the mean of its divisors is an integer number (24955998288882).

Almost surely, 2131141324341442 is an apocalyptic number.

131141324341442 is a deficient number, since it is larger than the sum of its proper divisors (68506661969614).

131141324341442 is an equidigital number, since it uses as much as digits as its factorization.

131141324341442 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 978666599632.

The product of its digits is 110592, while the sum is 38.

Adding to 131141324341442 its reverse (244143423141131), we get a palindrome (375284747482573).

The spelling of 131141324341442 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred twenty-four million, three hundred forty-one thousand, four hundred forty-two".

Divisors: 1 2 67 134 978666599563 1957333199126 65570662170721 131141324341442