Base | Representation |
---|---|
bin | 11101110100010110111001… |
… | …000110110110111000010011 |
3 | 122012022222201121101211221221 |
4 | 131310112321012312320103 |
5 | 114142104432030001004 |
6 | 1142525300102425511 |
7 | 36423435464665651 |
oct | 3564267106667023 |
9 | 565288647354857 |
10 | 131141342031379 |
11 | 388708048022a9 |
12 | 128600a2132297 |
13 | 5823763476004 |
14 | 24553bc175dd1 |
15 | 1026449775354 |
hex | 7745b91b6e13 |
131141342031379 has 2 divisors, whose sum is σ = 131141342031380. Its totient is φ = 131141342031378.
The previous prime is 131141342031373. The next prime is 131141342031397. The reversal of 131141342031379 is 973130243141131.
Together with next prime (131141342031397) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131141342031379 - 237 = 131003903077907 is a prime.
It is a super-2 number, since 2×1311413420313792 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131141342031373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570671015689 + 65570671015690.
It is an arithmetic number, because the mean of its divisors is an integer number (65570671015690).
Almost surely, 2131141342031379 is an apocalyptic number.
131141342031379 is a deficient number, since it is larger than the sum of its proper divisors (1).
131141342031379 is an equidigital number, since it uses as much as digits as its factorization.
131141342031379 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 163296, while the sum is 43.
The spelling of 131141342031379 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred forty-two million, thirty-one thousand, three hundred seventy-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.084 sec. • engine limits •