Base | Representation |
---|---|
bin | 1011111011010101111101… |
… | …0100101110101110100011 |
3 | 1201102200212120120000211021 |
4 | 2332311133110232232203 |
5 | 3204330221403040413 |
6 | 43520314501230311 |
7 | 2522315322244501 |
oct | 276653724565643 |
9 | 51380776500737 |
10 | 13114134424483 |
11 | 41a6744aa8144 |
12 | 1579735102397 |
13 | 7418718b1331 |
14 | 334a28351671 |
15 | 17b1de70918d |
hex | bed5f52eba3 |
13114134424483 has 2 divisors, whose sum is σ = 13114134424484. Its totient is φ = 13114134424482.
The previous prime is 13114134424441. The next prime is 13114134424513. The reversal of 13114134424483 is 38442443141131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13114134424483 - 213 = 13114134416291 is a prime.
It is not a weakly prime, because it can be changed into another prime (13114134424883) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557067212241 + 6557067212242.
It is an arithmetic number, because the mean of its divisors is an integer number (6557067212242).
Almost surely, 213114134424483 is an apocalyptic number.
13114134424483 is a deficient number, since it is larger than the sum of its proper divisors (1).
13114134424483 is an equidigital number, since it uses as much as digits as its factorization.
13114134424483 is an evil number, because the sum of its binary digits is even.
The product of its digits is 442368, while the sum is 43.
The spelling of 13114134424483 in words is "thirteen trillion, one hundred fourteen billion, one hundred thirty-four million, four hundred twenty-four thousand, four hundred eighty-three".
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