Base | Representation |
---|---|
bin | 11101110100010110111100… |
… | …101001011000010101001011 |
3 | 122012022222212202010202010222 |
4 | 131310112330221120111023 |
5 | 114142110042230203224 |
6 | 1142525310023300255 |
7 | 36423440115506021 |
oct | 3564267451302513 |
9 | 565288782122128 |
10 | 131141401412939 |
11 | 38870835280575 |
12 | 128600b9baa68b |
13 | 5823772867628 |
14 | 24553c5dd2711 |
15 | 102644eaa4b5e |
hex | 7745bca5854b |
131141401412939 has 2 divisors, whose sum is σ = 131141401412940. Its totient is φ = 131141401412938.
The previous prime is 131141401412881. The next prime is 131141401413031. The reversal of 131141401412939 is 939214104141131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131141401412939 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131141401412939.
It is not a weakly prime, because it can be changed into another prime (131141401402939) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570700706469 + 65570700706470.
It is an arithmetic number, because the mean of its divisors is an integer number (65570700706470).
Almost surely, 2131141401412939 is an apocalyptic number.
131141401412939 is a deficient number, since it is larger than the sum of its proper divisors (1).
131141401412939 is an equidigital number, since it uses as much as digits as its factorization.
131141401412939 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 93312, while the sum is 44.
The spelling of 131141401412939 in words is "one hundred thirty-one trillion, one hundred forty-one billion, four hundred one million, four hundred twelve thousand, nine hundred thirty-nine".
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