Base | Representation |
---|---|
bin | 11101110100010110111101… |
… | …110000101101100010001100 |
3 | 122012022222221001022202110020 |
4 | 131310112331300231202030 |
5 | 114142110112022041022 |
6 | 1142525311532142140 |
7 | 36423440433446202 |
oct | 3564267560554214 |
9 | 565288831282406 |
10 | 131141420112012 |
11 | 38870844892452 |
12 | 12860104307950 |
13 | 58237766b387b |
14 | 24553c869d072 |
15 | 102645154a35c |
hex | 7745bdc2d88c |
131141420112012 has 24 divisors (see below), whose sum is σ = 305996852940912. Its totient is φ = 43713777273600.
The previous prime is 131141420111993. The next prime is 131141420112019. The reversal of 131141420112012 is 210211024141131.
It is not an unprimeable number, because it can be changed into a prime (131141420112019) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 22130712 + ... + 27423552.
It is an arithmetic number, because the mean of its divisors is an integer number (12749868872538).
Almost surely, 2131141420112012 is an apocalyptic number.
131141420112012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
131141420112012 is an abundant number, since it is smaller than the sum of its proper divisors (174855432828900).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131141420112012 is a wasteful number, since it uses less digits than its factorization.
131141420112012 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7357609 (or 7357607 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 24.
Adding to 131141420112012 its reverse (210211024141131), we get a palindrome (341352444253143).
The spelling of 131141420112012 in words is "one hundred thirty-one trillion, one hundred forty-one billion, four hundred twenty million, one hundred twelve thousand, twelve".
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