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13114143011342 = 26557071505671
BaseRepresentation
bin1011111011010101111111…
…0101011111001000001110
31201102200220011201021210002
42332311133311133020032
53204330231102330332
643520315405244302
72522315455240202
oct276653765371016
951380804637702
1013114143011342
1141a674993261a
121579737b63692
137418735c9909
14334a29548b02
1517b1e0353562
hexbed5fd5f20e

13114143011342 has 4 divisors (see below), whose sum is σ = 19671214517016. Its totient is φ = 6557071505670.

The previous prime is 13114143011303. The next prime is 13114143011353. The reversal of 13114143011342 is 24311034141131.

It is a semiprime because it is the product of two primes.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3278535752834 + ... + 3278535752837.

It is an arithmetic number, because the mean of its divisors is an integer number (4917803629254).

Almost surely, 213114143011342 is an apocalyptic number.

13114143011342 is a deficient number, since it is larger than the sum of its proper divisors (6557071505674).

13114143011342 is an equidigital number, since it uses as much as digits as its factorization.

13114143011342 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6557071505673.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 13114143011342 its reverse (24311034141131), we get a palindrome (37425177152473).

The spelling of 13114143011342 in words is "thirteen trillion, one hundred fourteen billion, one hundred forty-three million, eleven thousand, three hundred forty-two".

Divisors: 1 2 6557071505671 13114143011342