Base | Representation |
---|---|
bin | 111101000100010101… |
… | …1001010001110000011 |
3 | 110112111111212121011202 |
4 | 1322020223022032003 |
5 | 4122034330044212 |
6 | 140125032531415 |
7 | 12321551620304 |
oct | 1721053121603 |
9 | 415444777152 |
10 | 131142034307 |
11 | 50687294439 |
12 | 214bb250b6b |
13 | c49c681c8b |
14 | 64c102a7ab |
15 | 362824e0c2 |
hex | 1e88aca383 |
131142034307 has 2 divisors, whose sum is σ = 131142034308. Its totient is φ = 131142034306.
The previous prime is 131142034301. The next prime is 131142034339. The reversal of 131142034307 is 703430241131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131142034307 - 212 = 131142030211 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131142034307.
It is not a weakly prime, because it can be changed into another prime (131142034301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571017153 + 65571017154.
It is an arithmetic number, because the mean of its divisors is an integer number (65571017154).
Almost surely, 2131142034307 is an apocalyptic number.
131142034307 is a deficient number, since it is larger than the sum of its proper divisors (1).
131142034307 is an equidigital number, since it uses as much as digits as its factorization.
131142034307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 29.
Adding to 131142034307 its reverse (703430241131), we get a palindrome (834572275438).
The spelling of 131142034307 in words is "one hundred thirty-one billion, one hundred forty-two million, thirty-four thousand, three hundred seven".
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