131142130401301 has 4 divisors (see below), whose sum is σ = 131150469078592. Its totient is φ = 131133791724012.

The previous prime is 131142130401259. The next prime is 131142130401349. The reversal of 131142130401301 is 103104031241131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131142130401301 - 2¹¹ = 131142130399253 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131142130401371) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4169315055 + ... + 4169346508.

It is an arithmetic number, because the mean of its divisors is an integer number (32787617269648).

Almost surely, 2^{131142130401301} is an apocalyptic number.

It is an amenable number.

131142130401301 is a deficient number, since it is larger than the sum of its proper divisors (8338677291).

131142130401301 is an equidigital number, since it uses as much as digits as its factorization.

131142130401301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8338677290.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 131142130401301 its reverse (103104031241131), we get a palindrome (234246161642432).

The spelling of 131142130401301 in words is "one hundred thirty-one trillion, one hundred forty-two billion, one hundred thirty million, four hundred one thousand, three hundred one".