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131142130413414 = 2374534329324783
BaseRepresentation
bin11101110100010111101000…
…000110010010111101100110
3122012100001202112212210210120
4131310113220012102331212
5114142113040341212124
61142525510224302410
736423464150063601
oct3564275006227546
9565301675783716
10131142130413414
11388710798283aa
1212860282171a06
13582385a8bba63
142455454b59338
151026493aa4d79
hex7745e8192f66

131142130413414 has 16 divisors (see below), whose sum is σ = 262284621668352. Its totient is φ = 43713983330888.

The previous prime is 131142130413391. The next prime is 131142130413467. The reversal of 131142130413414 is 414314031241131.

It is a super-2 number, since 2×1311421304134142 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10190334 + ... + 19134449.

It is an arithmetic number, because the mean of its divisors is an integer number (16392788854272).

Almost surely, 2131142130413414 is an apocalyptic number.

131142130413414 is an abundant number, since it is smaller than the sum of its proper divisors (131142491254938).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131142130413414 is a wasteful number, since it uses less digits than its factorization.

131142130413414 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30070131.

The product of its (nonzero) digits is 13824, while the sum is 33.

Adding to 131142130413414 its reverse (414314031241131), we get a palindrome (545456161654545).

The spelling of 131142130413414 in words is "one hundred thirty-one trillion, one hundred forty-two billion, one hundred thirty million, four hundred thirteen thousand, four hundred fourteen".

Divisors: 1 2 3 6 745343 1490686 2236029 4472058 29324783 58649566 87974349 175948698 21857021735569 43714043471138 65571065206707 131142130413414