Base | Representation |
---|---|
bin | 11101110100010111101000… |
… | …001001011000101101010011 |
3 | 122012100001202121101221212021 |
4 | 131310113220021120231103 |
5 | 114142113041043122004 |
6 | 1142525510253512311 |
7 | 36423464160006163 |
oct | 3564275011305523 |
9 | 565301677357767 |
10 | 131142131223379 |
11 | 3887107a2309a1 |
12 | 128602824a2697 |
13 | 582385ab13623 |
14 | 2455454cca5a3 |
15 | 1026493bb4d54 |
hex | 7745e8258b53 |
131142131223379 has 2 divisors, whose sum is σ = 131142131223380. Its totient is φ = 131142131223378.
The previous prime is 131142131223347. The next prime is 131142131223421. The reversal of 131142131223379 is 973322131241131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131142131223379 - 25 = 131142131223347 is a prime.
It is a super-2 number, since 2×1311421312233792 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131142131223679) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571065611689 + 65571065611690.
It is an arithmetic number, because the mean of its divisors is an integer number (65571065611690).
Almost surely, 2131142131223379 is an apocalyptic number.
131142131223379 is a deficient number, since it is larger than the sum of its proper divisors (1).
131142131223379 is an equidigital number, since it uses as much as digits as its factorization.
131142131223379 is an evil number, because the sum of its binary digits is even.
The product of its digits is 163296, while the sum is 43.
It can be divided in two parts, 131142 and 131223379, that added together give a square (131354521 = 114612).
The spelling of 131142131223379 in words is "one hundred thirty-one trillion, one hundred forty-two billion, one hundred thirty-one million, two hundred twenty-three thousand, three hundred seventy-nine".
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