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131142131223432 = 23372491821276637
BaseRepresentation
bin11101110100010111101000…
…001001011000101110001000
3122012100001202121101221221020
4131310113220021120232020
5114142113041043122212
61142525510253512440
736423464160006300
oct3564275011305610
9565301677357836
10131142131223432
113887107a230a3a
12128602824a2720
13582385ab13664
142455454cca600
151026493bb4d8c
hex7745e8258b88

131142131223432 has 192 divisors, whose sum is σ = 382626339071040. Its totient is φ = 37347187852800.

The previous prime is 131142131223421. The next prime is 131142131223451. The reversal of 131142131223432 is 234322131241131.

It is a nude number because it is divisible by every one of its digits.

It is a junction number, because it is equal to n+sod(n) for n = 131142131223393 and 131142131223402.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 473920218 + ... + 474196854.

It is an arithmetic number, because the mean of its divisors is an integer number (1992845515995).

Almost surely, 2131142131223432 is an apocalyptic number.

131142131223432 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131142131223432, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (191313169535520).

131142131223432 is an abundant number, since it is smaller than the sum of its proper divisors (251484207847608).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131142131223432 is a wasteful number, since it uses less digits than its factorization.

131142131223432 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 277972 (or 277961 counting only the distinct ones).

The product of its digits is 20736, while the sum is 33.

Adding to 131142131223432 its reverse (234322131241131), we get a palindrome (365464262464563).

The spelling of 131142131223432 in words is "one hundred thirty-one trillion, one hundred forty-two billion, one hundred thirty-one million, two hundred twenty-three thousand, four hundred thirty-two".