Base | Representation |
---|---|
bin | 11101110100010111101000… |
… | …100000010001100100010011 |
3 | 122012100001210000200210101212 |
4 | 131310113220200101210103 |
5 | 114142113044112122233 |
6 | 1142525511030250335 |
7 | 36423464262006113 |
oct | 3564275040214423 |
9 | 565301700623355 |
10 | 131142137223443 |
11 | 38871082659925 |
12 | 128602844b69ab |
13 | 582385c134668 |
14 | 2455455a0d043 |
15 | 102649449ca48 |
hex | 7745e8811913 |
131142137223443 has 2 divisors, whose sum is σ = 131142137223444. Its totient is φ = 131142137223442.
The previous prime is 131142137223401. The next prime is 131142137223469. The reversal of 131142137223443 is 344322731241131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131142137223443 - 28 = 131142137223187 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131142137223443.
It is not a weakly prime, because it can be changed into another prime (131142137222443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571068611721 + 65571068611722.
It is an arithmetic number, because the mean of its divisors is an integer number (65571068611722).
Almost surely, 2131142137223443 is an apocalyptic number.
131142137223443 is a deficient number, since it is larger than the sum of its proper divisors (1).
131142137223443 is an equidigital number, since it uses as much as digits as its factorization.
131142137223443 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 290304, while the sum is 41.
Adding to 131142137223443 its reverse (344322731241131), we get a palindrome (475464868464574).
The spelling of 131142137223443 in words is "one hundred thirty-one trillion, one hundred forty-two billion, one hundred thirty-seven million, two hundred twenty-three thousand, four hundred forty-three".
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